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25 1. L(9082+2) 2.1-2 (15+23782+2) 3.1-45+23481727) 4.1-967293 5. Considering the circuit, 2[0] 1[0] M ANA a) Find the volta

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L (Lion)) BS + S +2 partial fractions on both sides. Q : A (8°+2) + (s+c)s. seोर 25 A (83+2) +@ste)s da 2= AS²+2A + Be + csL Page 2] Set 5 Apply invorse la place Transform we know that t (b) = (NA) Cos at UH) tot (i= 645 et les ro) como este) e +Page 3) A (52+2) + S+c) Cstorno I see As+ aA + Bs? +BS + es + 295 82 (A+B) + s (Btc) +Qarcas. Compare s2 terms A+B=0 A=-B top31 28+1 | Page=4] F (SH) (810) EGH(141) Applying portion factions on both swas! 9S+1 Bstc 2st — for) (3+27 1) A CS2+2) +(85+c- Page 6 9. f equation can D Substitute e ty Center in a B(4) Apply forose Laplace Transform (52+2) ma t (en cata) - (+ e* *85°H = A (842) + (854) (s) 38 +1 ? As? +98 + 88+86 + CS +c 85?# = $(A+B) + s (B+C) +20 +C920 Compare s² terms AtB9 osta, BitConsider the Circuit TO - a find the voltage across the incluctor as a - fonction of time (2, 4)) using hoplace transformatio1 page-8) ucos La Co sep ]. cor de nes ( (part 3) vic) (to let (St)HS s(s+) 35+3 tl = 9S+1 . (sti S(+1) u, (s) = ast 2st SCSHPegleda] ३ (२+1) Can (st) ) + 3. (21) = Pa) (ब) A (s+५+ B (SH) ( (,) S+ ५० SY 3 (ack)+) = 8 () 8 (+a - 18 PHYS = +5 Big B- 5(pogle.co] 4,00* CRUJ Apply inverse laplace transform. L (4.c)) - get 1 set 148 = get +5€4+) v. In tt) > g 5 1333+ lv. This

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