Question

LEN P4-3 In cach case, determine the resultant moment of the forces acting about the x, y, and axes 4. In each case, set up the determinant needed to find the moment of the force about the axes F +2 + N F- 3- N Proh Prob. P4-3

Answer 1

Anticlockwise moment is taken as positive and clockwise moment is taken as negative.

Moment of a force is given by:-

Moment = Force x Perpendicular distance

@ Mx = -(160 x 3) = -300 Nm My = -(200x2) = -400 Nm M₂ = - (300x2) = -600 N-m

Ma My M sox0.5 = 25 Nom (400x 0.5 -130003) 100x 3 = 300 Nom = -700 N = = m

h Mx = 300/2) -(oox 2) = 400 N-m My = 5x1 + 400 x 0.5-300x1 e - sonom M₂ - (200 x 1) - 200 N-m