The diagramme can be constructed as -
Majority carrier concentration vs. inverse temperature for an extrinsic semiconductor. In the ionization regime, donor atoms are partially ionized. Then in the saturation regime where donors are fully ionized and carrier concentration is a constant. Finally, at high temperatures there is the intrinsic regime where it behaves like an intrinsic semiconductor. The temperatures corresponding to these depend on the donor concentration.
The vertical dotted line marks room temperature.will not change the conductivity. Thus, electrical devices can be formed with very little variation in their electrical properties during normal operating temperatures.
Low temperature regime (T < Ts) - At absolute zero there are no ionized carriers. Valence band is full and the donor level is full and conduction band is empty. As temperature is increased, electrons are excited from the valence band and the donor level to the conduction band. But since the valence band ionization energy is of the order of eV , at low temperature the number of electrons excited from it are negligible compared to the electrons from the donor level. So the valence band contribution can be ignored and only electrons from the donor level are excited to the CB. This regime is called ionization regime and extends up to a temperature until all the donor electrons are ionized. The electron concentration (in CB), in the ionization regime, is given by
∆E is the ionization energy of the donor level i.e. the energy difference between the donor level and the conduction band.
Medium temperature regime (Ts < T < Ti) - Above the saturation temperature the donor levels are completely ionized so that n = Nd. As temperature keeps increasing there comes a temperature when the electrons from the valence band (intrinsic carriers) becomes comparable in concentration to Nd. This temperature is called the intrinsic temperature, T.
A ionization regime at low temperature, a saturation regime where the electron concentration is nearly a constant, and a intrinsic regime where the semiconductor behaves like an intrinsic semiconductor. In Si, this saturation regime is around room temperature so that the carrier concentration is a constant and independent of temperature.
Thus doping in a semiconductor has 2 functions :-
1. It increases the conductivity by preferentially increasing either electron or hole concentration. The conductivity can be precisely tuned by controlling the type and amount of dopant.
2. The majority carrier concentration is a constant and temperature independent (near room temperature) so that small temperature variations.
6. Explain the variation of carrier concentration of an extrinsic semiconductor with respect to 1/7 shown...
Draw and label (valence and conduction) a band diagram for an extrinsic semiconductor with silicon as the substrate and indium as the dopant. (Please make it as least 1/3 of a page in size.) Write down on the page whether it is an n-type or a p-type. 1 i. - BIO E % Explain briefly how you would adjust the semiconductor in the previous question if you wanted to allow a higher limiting current to pass through. (type your answer...
1. Define the majority carrier concentration in an n-type Si semiconductor in terms of the conduction band edge energy Ec and the Fermi energy Ep 2 marks Find an expression for Ec - Ep, i.e, the difference between the conduction band edge energy and the Fermi energy in terms of the donor concentration Np. 4 marks Determine the concentration of donor impurity atoms that must be added to silicon that Ec Ef = 0.2 eV So 4 marks
1. The carrier effective masses in a semiconductor are m* = 0.621m, and m.* = 1.4m. Determine the position of the intrinsic Fermi level with respect to the center of the bandgap at T = 300 K.
1. The carrier effective masses in a semiconductor are m = 0.621m, and m* = 1.4m, Determine the position of the intrinsic Fermi level with respect to the center of the bandgap at T = 300 K.
QUESTION TWO (9 marks total) (a) An n-type semiconductor has a uniform excess minority carrier concentration of 5 x 1015 cm3 and minority carrier lifetime T 1.5 us in the bulk, and minority carrier lifetime Ts 0.2 us at the surface. D 10 cm2/s. Assuming zero applied electric field and low-level injection: Determine the steady-state excess carrier concentration at the surface What is the generation rate? Enter calculated values in the boxes below (5 marks) (Hint: steady-state means time-invariant; that...
Define the majority carrier concentration in an n-type Si semiconductor in terms of the conduction band edge energy E, and the Fermi energy E. 1. 2 marks Find an expression for Ee -Ef, i.e, the difference between the conduction band edge energy and the Fermi energy in terms of the donor concentration ND. 4 marks Determine the concentration of donor impurity atoms that must be added to silicon so that Ec- E0.2 eV. 3 marks
Semiconductor Physics: A semiconductor has a intrinsic concentration of 1010 cm-3 and has donor impurity concentration of 1015 cm-3. Light is shined (uniformly) upon the sample generating 5*1019 electron-hole pairs.cm-3s-1 with a minority carrier lifetime of 10-6 s. What is the net electron-hole recombination rate? I think at steady state, the electron-hole recombination rate is the same as the generation rate. But the current circumstances of the question make me doubt that assumption or conclusion (the question is 4 marks).
Problem 3: pn Junction -- Carrier Concentration Profiles The steady-state carrier concentrations inside a Si pn step junction diode maintained at room temperature are shown in the plot below: п or p (log scale Pp -106 10 102 a) Is the diode forward or reverse biased? Explain briefly. b) Do low-level injection conditions prevail in the quasi-neutral regions of the diode? Explain briefly. c) What are the p-side and n-side net dopant concentrations NA and ND, respectively? d) Determine the...
CLARO P.R. LTE 10:40 p. m. 29% 0 4 de 6 Question 7. (12 points) (a) What is the major charge carrier in p-type semiconductor? What is the major charge carrier in n-type semiconductor? (b) Plot out the BAND STRUCTURES and C-T curves of n-type and p-type semiconductors, respectively. 400K n-type semiconductor p-type semiconductor Question 8 (14 points) Based on electronegativity table below, in one picture please e rate Al Al 1 27
e Calculate the position of EF with respect to E. 5. Explain why holes are found wny holes are found near the top of the valence band, whereas conduction electrons are found at the bottom of the conduction band. O. Using the Figure 3-17 in your text (also attached), fill in the following table: Semiconductor 300°K 400°K 500°K Ge GaAs For Ge at 500°K and Si at 400°K, show on the attached graph how you determined the value you put...