for the hanging block , force equation is given as
T2 = mg
T2 = 2.27 x 9.8 = 22.25 N
since the rope is same
T1 = T2 = 22.25 N
parallel to the leg , force equation is given as
F = T1 Cos30 + T2 Cos30
F = (22.25 + 22.25) Cos30
F = 38.5 N
help with this homework please! ICURE B-42 Problem 25 26. BIO Tra action After a skiing...
After a skiing accident, your leg is in a cast and supported in a traction device.Find the magnitude of the force F exerted by the leg on the small pulley. (By Newton's third law, the small pulley exerts an equal and opposite force on the leg.) Letthe mass m be 2.50 kg .T1= 30.0 degreesT2=30.0 degrees