Question

Water vapor is cooled in a closed, rigid tank from T1=660 degree Celsius and p1= 100 bar to a final temperature of T2=320 degree Celsius. Determine the final specific volume, v2 in m^3/kg, "AND THE FINAL PRESSURE, P2, IN bar".

Answer 1

Given, T_1 = 660 degree C P_1 = 100 bar T_2 = 320 degree C # Using Table-A4 (Superheated water), at T_1 = 660 degree C and P_1 = 100 bar- V_1 = 0.04048 + (660 - 640)/(700-640) times (0.04358 - 0.04048) = V_1 = 0.041513 m^3/kg # Given that the tank is closed, hence total mass will be constant. Also, tank is rigid, hence the volume will be constant. Specific volume, V = V/m = constant = V_2 = V_1 V_2 = 0.041513 m^3/kg Answer # Using Table - A4 (Superheated water), at T_2 = 320 degree C and V_2 = 0.041513 m^3/kg- P_2 = 40 + (0.041513 - 0.06199)/(0.03876 - 0.06199) times (60-40) = P_2 = 57.63 bar Answer