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4. A gear is manufactured from SAE1045 hardened steel having pitch diameter D= 9.0 inches, having (13+12] 54 teeth, pressure
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4. Given SAE 1045 hardened stel Dp = a inches NG = 54 teeth Design HP = ashp which will operate & hours per day @ 600 opm $ =Wt = 33,000 x 25 1413 W = 583.864 119 lbt (6) Calculate the minimum face width (bow) SAE 1045 stel Sy & heildstregth) = 45 kp= = 0.166 inch module = Pitch diameter Number of teeth m = 0.166 Inch 9 Inch 54 = (2.1775) ( 583.864) (bw) (0.166) Co. 412) 1Any doubts, post below in comments.

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