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The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.80. If the probabi
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Answer #1

Question 3)

Answer)

P(a or b) = p(a) + p(b) - p(a and b)

Here

P(car) = 0.65

P(computer) = 0.8

P( car and computer) = 0.55

So, P(car or computer) = 0.65 + 0.8 - 0.55 = 0.9

Question 5)

Probability is given by favorable/total

Total = 18 juniors + 10 seniors = 28

Favorable = seniors or females = 10+6 = 16

{As 6 are females among 18 juniors)

Required probability is 16/28 = 0.57142857142

Or 4/7

{4th question is incomplete, p() in bracket is not completely visible}

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The probability that s student owns a car is 0.65 and the probability that a student owns a computer
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