Resultant Force Fr = (125*4/5* cos 20 degree + 400 cos 45 degree)i + (125*4/5* -sin 20 degree + 400 cos 60 degree) j
+ (125*3/5 - 400 cos 60 degree) k
= 377 i + 167 j - 125 k N
magnitude = sqrt(377^2+167^2+125^2)
= 431 N
direction angle with +x axis , alpha = arccos(377/431) = 29 degree
with +y axis, beta = arccos(167/431) = 67 degree
with +z axis gamma = arccos (125/431) = 107 degree
Clearly draw diagrams and show step by step details on how to solve this problem 2-69....
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how would you draw the final answer Determine the magnitude and coordinate direction angles of the resultant force. Draw your final answer at the end of your solution in a 3D coordinate system. Label the angles on your drawing. F-400 N 135 60° 601 F = 500 N
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