Question

please help solve for what is asked in orobkems A-H and the free body diagrams as well. Will upvote if correct
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B 4 m 6 m 3 m 12 m 2 m F=80 N Determine the projected component of the force acting along the axis AB of the pipe. 60° A The 30kg pipe is supported at A by a system of five cords. Determine the force in each cord for equilibrium. F 60° 135° 60° 60° 30° (4 m, 4m, -2m) If F1 -8.26 KN, F2 3.84 KN, and F3 -5.56 KN, determine the magnitude and direction of F required for equilibrium. 2.5 ft C 4.5 ft 3 ft A 1.5 ft H I 3 ft D 1.5 ft Determine the force in cables DA, DB, and DC if the bucket weighs 20 pounds. 4 m 260 N 3 m 1312 2m-B 5 m 400 N 30° 2 m Determine the directional sense and the magnitude of the resultant moment about the origin. F=500 lb F 375 lb 4 B. 0.3 ft 8 ft 6 ft 5 ft- I 30 F3 160 lb For each of the three forces acting on the beam, calculate the moment about point A. 4 m F-(60i-30j 20k) N 3 m 7 m 4 m 6 m 2 m I Determine the moment of the force F about point P. Express the answer as a Cartesian vector. 200 mm 400 mm 600 mm The force acts along the diagonal shown and has a magnitude of 175 N. Determine the moment of the force about point A.

Answer 1

B.) Determining the force in each cord.

☆ If the system of forces are in coplanar, concurrent but not collinear and if all the forces are in equilibrium then the magnitude of force is directly related to the angle opposite to the force.

☆ It is only valid up to 3 force system.

☆ The formula can be seen from given below figure.

LAM TH£0R£M Slnd gin B

☆ Now, jump to the question, and we do this in two steps.

☆ First select the point A and solve for the Force on cord AE and Force on cord AB.

Let, the value o 10ms 303 Wn 30OCT AB LAMI'S THAORE 120 FAR PAS 150 Soo sin120 gin1 so Sin So PAB sin (so° sin(20 300 AE sin 150 gin 1209 Fag 13.2051 AB g|n 90° sln1E0 FAB 346.A1 C

☆ Now, we obtain the value F_AE and F_AB

☆ Go for the point B and solve for the forces on chord CB and BD.

A Point B LAMT3 THORE 1200 ain l13-13 EB.9714S FAB FAB sinl13 13 B.9tiu FeB = 301.350 sin 113.13 sin 120° 326.223T,

C.) Please go with the below figure.

The formula is used, for finding vector is

Vector = scalar × (unit vector), ( here cross (×) is simply multiplication sign, it is not cross product).

☆ In below figure we find the F₃ vector.

ayatem oroce is exomple T5i3 Con- Originates ^om origin and moyes towasd La,a,-2) Let oigjn O (o,o0) A 'as (4,4,-2) designate Point Oigin and point we (4, A,-2) unit vectos vectaarScalar x SA = 6 Ai 4j-2k; \õÁ1 = Jj6+16+4 OA = SA \ +

☆ In below figure, we had calculated F₂ and F₃ vectors,

☆ There are two methods for finding unit vector,

1.) If we had given points then form the vector and divide it with its magnitude.

unit vector = Vector ÷ |Vector|   ((unit vector = vector ÷ its magnitude))

2.) If we had given angles then we use,

cos(0)icos(0)yj+cos(0).k n =

☆ And sometimes we are only with two angle, and we want to calculate the third angle, then use,

cos( cos(0)cos(0)1

☆ Now see the below figure,

TFe disecion Forsee vector 2. x= 135 cose oaej+coza 0 o S3 + 0.5*) P2 Fors The discetion o osee vectos 1. Poom this id entity, calculate Oz we Con Cs30x cos'a D 25 + cosazz 1 O.76 R R(eosgi+coaej cai) ECoB660i+ O55+ o*)

☆ Now, write the force in vector form, for all the force vector F1, F2, F3. In term of their components.

Resultant ector. A=8.26 C0.8661 +0.55) SE1ヤ+!91891t 2.84o307i 0.550.6k) 2 Ði 1-923 92) E99.0) = 0-6635-033k) 5.56 (O6 F33.0852i +3.408552 18515

☆ Now, simply add all the x component of F1, F2, F3 for obtaining x component of Resultant F,

☆ And do the same for y and z component.

☆ For resultant,

F2 F2F R =

1В316+ -2.149)4330ВБ2) (4-13 923.t0852)) 32 - \-g515) o 0.0685k 8.146781+ 9.458523 FR=J149958500685 Pr- 8:1467в j=9.35852 fr 12.Hr Pez0:058Б TCL 1C Пc

☆ For finding the direction of the resultant vector we simply follow the Below figure.

DIRECRIOnm cO86x ニ Cose8.14678 9.75852 cosey 1 COS07 = O.O685 12.

☆☆ Please comment below if you have any doubt regarding this question before rating this answer.☆☆

☆ Solving all the problem with specified time limit, it is not possible to do all problem.