Question

For each of the following trusses, determine the force in each member of the truss, and state if the members are in tension or compression. 3 kN 1.5 m V 0 = 30° В 2 m — 2m — 4 kN 6 ft- 8ft 8 ft 500 lb Тв 100 lb 800 lb 600 lb 60° 3 ft

Answer 1

م کہ کے Ax + 3 - Rc Coxbo = 0 0 Ay - 4 + Resine = o IB 66 t 30 وما ، है। 2 m 4x2 – 3x1.5 = 0 4 Ay = 35 Putting in o ma Ay - 0.875 KN n Samp=1s m 0.875-4+ Rc Sinbo = 0 Resonga - u - O. 875 The= 3.61 KN puiting in o 3.6 18 Cosbe Ax & 3- AX= 1.2 KN 0.875 IN Sna I aking point A HHHHH 1- 26M Acling FAB+ FAD CORD E fyco PAR sind + 0-87550 FAD = -0.875 - Sin 36.99 11.458 Compression = FAD

Efn=o 12+ FAB & Paoload to TAB - - 1.458 X Co $36.9- [FAB= 2.366 Compression Taping toint. B AFBD 7 ppe o FBD = 4N tension Euro FAB = FBC FBc = -2.3.66 Compression taking sount D Pas sind Taclind Eve LEBD tand= 7 I FADES 7 Foccaso = 5313 3 ) 28 Staro 3+ ficring = Fassing 3t FD CSMS 3.13 - - 1.458 Sin 53:13 FDC = -5:208&N compression.

& o soolb اسکے۔ & Toolb Ax = 500 lb Taking moment About A EMA- - 5008 8 - 100x 6 & REX 16 = 0 - 4000 - 600 t 16 Rc=0 IGRc = 4600 FABsine & focsino Rci 287.5lb FABA Taking soint B 4 sooth a FBcCord FAB Copo 100 BC Coop FAB Coso +500 tema = 8 ИТЬ В то + Суиф loo 0 - 5313 taking guinte Are tano = 8 - 45° f Be Cuso FAC A & Busine Rc = FBssing Efa=0 Frocco&o & fac=0 - 406.6 cupus - FAC FAC= 287 Compression FBC = Ra sind 406.6 lbl IFBc =

600 Putting value of foc en 6 FARCO 53.13 +500 = 406.6 cos 450 TAB - - 354.15 Compression. foo soubo Gooley воосква t ♡ Taping joint e 74 Poolop gom FBC 7800 Singo Chaco PBC = -800 Copbo = 400 Compression = foc o Fep в обливі во 2 SD = Fe = 692.8 Compression 600 Taking sout B ABD sine Be tano - 3 FBA O=3670 FBD Coro FIO EBC & FBD sine 36 7) = 6 FBD2-FBe -(-400) Son 367 PBD = 666.67 Tension

Efy=0 600 + EBA & FBD Coso =0 FBA = -600 - FBD Caso TBA - 600 - 66667Co8367 IBA -- 1133.33 Compression