Question

please solve all three otherwise I will give negative rating.

Force Facts at point B on the semicircular bent bar. O F = 6 kN 8.4 m Determine the moments of the force about points A and C in kN. m. magnitude direction kNm counterclockwise Mc KN.m magnitude direction clockwise Determine the shortest distances from points A and C to the line of action of the force in meters. da = m de= m Force Facts at point B on the semicircular bent bar. F3 KN 5.9 m Determine the moments of the force about points A and C in kN. m. kNm magnitude direction --Select--- Mc kNm magnitude direction ---Select-- Determine the shortest distances from points A and C to the line of action of the force in meters. A = Force F = 698 lb acts from A towards B. 2.5 in 5 in c2 in Determine the moments of the force about points O and C. (Express your answers in vector form in inch-pounds.) Mc-( in lb

Answer 1

X - Anos :- DAB - - 0 IN <> 34 y <- Bloo) 504 co-ordinate of pount o = 18.00) Co-ordinate of Point A = (814, 8.4 m. corordynate of Point c = 18.4,-8.4m . F = Froso i + Fsinoj Fia= 6x 4 9 + 6x3 = 24.8 +3.65 Mo = -4.8 x 8.4 + 3.6 x 8.4 2 Positive - - - 10.08 KN-m c o negative out 10.08 KN-m in counterclockcouse moc = 408x 8.4+ 3.6x8.4 = 70.56KN-m 70.56 N-m in clockwise Fanation of line of action of force - y-o= m(a-o) => y = tas(x) PT => y = 3x - 3x-44 = 0 sistance des perpendicular A El shortest fjistance - 8 do = e 3x8.4 - 4x8.4) (3)²+(4) 2 = 1.68m (x = 8.4 dB = B - gatbytc y to d=19x + by, tch Joztle 1 sx 1348.4 - 4x (-8.4) J (3) 271872 - 11.76 m

In 2014 Problem ssituation jos same values are & ifferent B = 10,0) A15.g, sog) Bls.g, 5-gmbh 2² = Fcoso j + f sinoj = 3x4 + 3x 33 set = (2-4 å +1-8 3 ) KN MA= -2.4x 50g + 1188 5.9 2 Positive = - 3:54 KN-M 9 Negative 3.54 KN-m in counter clock wise mg = 2.4x5.9 + 1.8x59 = 24.78 KN-m clockwyse Eayation of time y-o= Z (2-0) da = 13x5.9 - 4x5.g) = sig = 1.8m - dc = 13x5.9 - 4x (-5.9)) = 41.3 = 8.26m J (3) ²7 (4) 2те ръон em F = 698 db o 10,0,0) Alo, 5,205) so B(2,0,0) n (2,5, o) in AB = AB = [(2-0) J + (0-5)j + (0-2.5) Ê] TABT 112)2+(-5)2+(-2-5)2 529-sj -2.5²] = 0.33689 -0.8428-0.92K 5.937 P = IF? AB = 698 (0.3368 j - 0.842j-0.92K) =(235.086 j - 587.7161 - 293.16 It