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Example The average number of milligrams (mg) of sodium in a certain brand of low-salt microwave froren dinners is 660 mg, an

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Answer #1

Let X be the variable here following N(660,352).

Required probability = P(X<650)

X =PG 650 – 660 - 660 35 35

P(Z < -0.28)

(where, Z X - 660 35 N(0,1)]

= Φ(-0.28 , where (.) is cdf of standard normal distribution

=1 - Φ(0.28) , since a standard normal distribution is symmetric about mean 0.

==l-0.6103 -0.3897

Therefore, probability that the sodium content in the selected dinner will be less than 650 mg will be approximately 0.3897 i.e. 38.97%.

[The values are obtained from standard normal distribution table given below:

P(X) - -L Odt * ~ N0,1) 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.5000 0.5040 0.5060 0.5120 0.5160 0.5199 0.523]

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