(2 points) Let f(x) be the pdf of a normal random variable with mean -100 and...

Question

Question

(2 points) Let f(x) be the pdf of a normal random variable with mean -100 and variance 10,000. Use this information to comput

Answer 1

Answer #1

To compute the integral we have to compute the area between -94 and -40

SD = sqrt(Variance) = sqrt(10000) = 100

f(x) ~ Normal(Mean=-100, SD=100)

Converting to standard normal

-94:

z = (-94+100) / 100 = 0.06

-40:

z = (-40+100) / 100 = 0.6

P(-94 < f(x) < -40) = P(0.06 < z < 0.6) = P(z<0.6) - P(z<0.06) = 0.72575 - 0.52392 = 0.20183

Answer B. 0.2

Answer 2

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