Question

• Reflection. A pulse on a string has the dimen- sions shown in Fig. E15.30 at t= 0. The wave speed is 40 cm/s. 4.0 mm (a) If point 0 is a fixed end, draw the total wave on the string 15.30 wave Figure E15.30 4.0 mm 4.0 mm k* v = 40 cm/s 8.0 mm 15 ms, 20 ms, 25 at t = ms, 30 ms, 35 ms, 40 ms, and 45 ms. (b) Repeat part (a) for the case in which point O is a free end.

Just part (a).

Please show all steps and focus especially on units; I`m not used to seeing ms or whether or not it is best to convert to meters or millimeters.

Answer 1

@ the distance troueled by the Nave is given by - deuxtu 40cm = 400mm For t=15ms d=(400mm) (15 ms) d=6mm For t=20ms d=1400 mm) (20 ms) d=8mm d =(400 mm) (25 ms) d=10mm For t= 25 m, For t=3oms d= (400mm) (30 ms) d=12mm the pulse For t=35m is inverted For t= 40ms d= (400mm) (35 ms) d=1umm d= (400 mm (40 ms) de 16 mm d = (400 mm) (45 mu d=8mm t=45m)