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A 34.0 kq block at rest on a horizontal frictionless air track is connected to the...
A 21.0kg block at rest on a horizontal frictionless air track is connected to the wall...
A 21.0kg block at rest on a
horizontal frictionless air track is connected to the wall via a
spring. The equilibrium position of the mass is defined to be at
x=0. Somebody pushes the mass to the position x= 0.350m, then lets
go. The mass undergoes simple harmonic motion with a period of
5.00s. What is the position of the mass 3.950s after the mass is
released?
Consider the same mass and spring discussed in the previous
problem. What is...
A 35.00 kg block at rest on a horizontal frictionless air track is connected to the wall via a spring. The equilibrium position of the mass is defined to be at x = 0. Somebody pushes the mass to the position x = 0.35 m, then lets it go. The mass undergoes
A 35.00 kg block at rest on a horizontal frictionless air track is connected to the wall via a spring. The equilibrium position of the mass is defined to be at x = 0. Somebody pushes the mass to the position x = 0.35 m, then lets it go. The mass undergoes simple harmonic motion with a period of 3.30 s. a) What is the position of the mass 2.77 s after the mass is released? b) What is the magnitude of the maximum acceleration the...
A 21.0kg block at rest on a horizontal frictionless table is connected to the wall via...
A 21.0kg block at rest on a horizontal frictionless table is
connected to the wall via a spring with a spring constant
k=34.0N/m. A 3.90×10-2kg bullet travelling with a speed of 550m/s
embeds itself in the block. What is the amplitude of the resulting
simple harmonic motion? Recall that the amplitude is the maximum
displacement from equilibrium.
14. 1pt A 21.0kg block at rest on a horizontal frictionless table is connected to the wall via a spring with a spring...
A block of mass 6.00kg is connected to a spring on a horizontal frictionless surface. By...
A block of mass 6.00kg is connected to a spring on a horizontal frictionless surface. By stretching the block and then releasing it, the block-spring system undergoes simple harmonic motion. The block’s position as a function of time is given by x = 45.0 cm cos(3pi(t) - pi/3) a. Determine the angular frequency and period of the motion b. Determine the amplitude c. Determine the phase angle e. Determine the time when the position x = -18.0cm f. Determine the...
A horizontal mass-spring system consists of a block (m=1.5 kg) on a frictionless to connected to...
A horizontal mass-spring system consists of a block (m=1.5 kg) on a frictionless to connected to a spring (k = 750 N/m). The system is initially at rest and is in equilibrium MI Second DIOCK (M=1.5 kg) approaches with a speed of 3.5 m/s and undergoes all inelastic collision with the first block (i.e.. they stick together after the collision). (a) What is the amplitude of the resulting simple harmonic motion (in cm)? (b) What is the angular frequency (w)...
1. A block of mass 6.00kg is connected to a spring on a horizontal frictionless surface....
1. A block of mass 6.00kg is connected to a spring on a horizontal frictionless surface. The spring constant is 280N/m. The block-spring system undergoes simple harmonic motion. At a time t=0s, the position of the block x= +A and its velocity vx= 0. At t=2.50s the position x = -12.0 cm No credit awarded without correct units! a. Determine the angular frequency and period of the motion b. Determine the amplitude c. Determine the phase angle d. Write the...
A 33.0 kg block at rest on a horizontal frictionless table is connected to the wall...
A 33.0 kg block at rest on a horizontal frictionless table is connected to the wall via a spring with a spring constant k= 25.0 N/m. A 0.028 kg bullet travelling with a speed of 540.0 m/s embeds itself in the block. What is the amplitude of the resulting simple harmonic motion? Recall that the amplitude is the maximum displacement from equilibrium. (in m) A: 5.66×10-2 B: 8.21×10-2 C: 1.19×10-1 D: 1.73×10-1 E: 2.50×10-1 F: 3.63×10-1 G: 5.26×10-1 H: 7.63×10-1...
A 21.0kg block at rest on a horizontal frictionless table is
connected to the wall via a spring with a spring constant
k=34.0N/m. A 3.90×10-2kg bullet travelling with a speed of 550m/s
embeds itself in the block. What is the amplitude of the resulting
simple harmonic motion? Recall that the amplitude is the maximum
displacement from equilibrium.
14. 1pt A 21.0kg block at rest on a horizontal frictionless table is connected to the wall via a spring with a spring...
A horizontal mass-spring system consists of a block (m=1.5 kg) on a frictionless to connected to a spring (k = 750 N/m). The system is initially at rest and is in equilibrium MI Second DIOCK (M=1.5 kg) approaches with a speed of 3.5 m/s and undergoes all inelastic collision with the first block (i.e.. they stick together after the collision). (a) What is the amplitude of the resulting simple harmonic motion (in cm)? (b) What is the angular frequency (w)...
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