Homework Answers
Yes it is possible that an object with constant acceleration can reverse the direction of motion.
Example : an object thrown vertically upwards has an initial velocity in upward direction but a constant acceleration is acting on the object which is directed vertically downwards. Now as it reaches the highest point , it starts to fall downward with the same acceleration 9.8 m/s^2 acting vertically downwards. Therefore, in this example a constant acceleration has reversed the direction of motion.
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depicts the motion of a particle moving along an x axis with a constant acceleration. The...
depicts the motion of a particle moving along an x axis with a constant acceleration. The figure's vertical scaling is set by xs = 6.60 m. What are the (a) magnitudeand (b) direction of the particle's acceleration ( +x denote 1 , 0 - otherwise )?
7. [2 points] A particle is moving at a constant speed in a circular path centered...
7. [2 points] A particle is moving at a constant speed in a circular path centered at the origin on an xy coordinate system. At one point (x=4m, y=0), the particle has a velocity of 5ġ m/s. a. State whether the particle is moving clockwise or counter-clockwise on the circular track. b. What is the constant speed of the particle throughout its circular trajectory? c. What is the acceleration (expressed as a vector) of the particle when it is at...
please explain in depth 5 Figure 2-20 gives the velocity of a particle moving along an...
please explain in depth
5 Figure 2-20 gives the velocity of a particle moving along an axis Point 1 is at the highest point on the Figure2-19 Question 4 curve; point 4 is at the lowest point; and points 2 and 6 are at the same height. What is the direction of travel at (a) time-0 and (b) point 4? (c) At which of the six numbered points does the particle reverse its direction of travel? (d) Rank the six...
At t = 0, a particle moving in the xy plane with constant acceleration has a...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.60 s, the particle's velocity is vector v = (8.90 i + 7.70 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...
At t = 0, a particle moving in the xy plane with constant acceleration has a...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.70 s, the particle's velocity is vector v = (7.40 i + 6.90 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...
please i need help asap Problem 1 The acceleration of a particle moving only on a...
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with reason please. Velocity and Acceleration Vectors An object is moving with an initial velocity along...
with reason please.
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At ti = 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise...
At ti = 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is a = (4.00m/s2) + (8.00m/s2) At t2 = 6.00 s (less than one period later), the acceleration is a = (8.00m/s 2) - (4.00m/s) The period is more than 2.00 s. What is the radius of the circle? Number Units
This figure (|a| = 14.5 m/s2) represents the total acceleration of a particle moving clockwise in...
This figure (|a| = 14.5 m/s2) represents the total acceleration of a particle moving clockwise in a circle of radius r = 1.70 m at a certain instant of time. (a) For that instant, find the radial acceleration of the particle. m/s2 (toward the center) (b) For that instant, find the speed of the particle. m/s (c) For that instant, find its tangential acceleration. m/s2 (in the direction of the motion)
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A particle moving with a constant acceleration has a velocity of 20 cm/s when its position is x = 10 cm. Its position 4.0 s later is x = - 30 cm. What is the acceleration of the particle? Select one: A. 5.0 cm/s2 B. 15 cm/s2 O C. 10 cm/s2 D. - 15 cm/s2 O E. - 5.0 cm/s2
7. [2 points] A particle is moving at a constant speed in a circular path centered at the origin on an xy coordinate system. At one point (x=4m, y=0), the particle has a velocity of 5ġ m/s. a. State whether the particle is moving clockwise or counter-clockwise on the circular track. b. What is the constant speed of the particle throughout its circular trajectory? c. What is the acceleration (expressed as a vector) of the particle when it is at...
please explain in depth
5 Figure 2-20 gives the velocity of a particle moving along an axis Point 1 is at the highest point on the Figure2-19 Question 4 curve; point 4 is at the lowest point; and points 2 and 6 are at the same height. What is the direction of travel at (a) time-0 and (b) point 4? (c) At which of the six numbered points does the particle reverse its direction of travel? (d) Rank the six...
with reason please.
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At ti = 4.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is a = (4.00m/s2) + (8.00m/s2) At t2 = 6.00 s (less than one period later), the acceleration is a = (8.00m/s 2) - (4.00m/s) The period is more than 2.00 s. What is the radius of the circle? Number Units
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