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A particle of mass 5 kg is released from point A a

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Answer #1

a) particle speed at point B = sqrt(2 * 9.8 * 1.8)

                                             = 5.939 m/sec

      particle speed at point C = sqrt(2 * (9.8 * 1.2 + 0.5 * 5.939 * 5.939) )

                                             = 7.667 m/sec

b)   Net work done =    1/2 * 5 * (7.667 * 7.667)

                                = 147 J

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