A Pelton wheel turbine (at maximum efficiency) is designed for a water head H of 80...
A Pelton wheel with an efficiency of 85% is used to produce hydroelectric power from flow of water behind a dam with an elevation head of 420 m. The average radius of the wheel and its angular velocity are 2.0 m and 220 rpm, respectively. This turbine works at its optimum rotation rate (which produces maximum power). The turning angle of the buckets is ? = 165° and nozzle diameter is given as 8.00 cm. a. Calculate volumetric flow rate...
A Pelton wheel installation uses a water jet of 75mm diameter to drive a wheel with the buckets on a diameter of 0.9m. The deflection angle of the buckets is 160 o .The relative velocity of the water is reduced by 12% while moving across the buckets. The rotational 8 speed is 320rpm, the total pressure behind the nozzle is 0.7Mpa and the velocity coefficient of the nozzle is 0.98. Determine 5.1 the hydraulic power developed by the wheel, 5.2...
QUESTION 7 A prototype Pelton wheel turbine is to operate under a head of 350 m at 250 rpm. A model develops 2 kW under a head of 16 mat 420 rpm. It uses 0.09 m/s of water. Find for the prototype. (b) the scale-ratio, Le. the ratio of the prototype wheel diameter and model wheel diameter
Mechanical lab please answer all steps 2. A Pelton wheel is used to produce hydroelectric power and the performance 62.4 lb/ft data are collected in the following table. Specific weight of water 1 hp 550 ftlb/s. Water supply line pressure Turbine speed Shaft torque (lbft) Flow rate (cfm) (psig 80 300 50 If water supply pipe diameter is 20 inches and turbine wheel radius is 20 inches, calculate the hydraulic head in ft, jet velocity, speed ratio, hydraulic horse power,...
Determine the efficiency of a water turbine The buckets of a Pelton wheel revolve on a mean diameter of 2.0 m at 1600 rev/min. The jet velocity is 1.5 times the bucket velocity. The water flow rate required to produce a power output of 2.5 MW is 120 kg/s. The blade friction coefficient is 0.97. The deflection angle is 165⁰ . Determine the efficiency of the water turbine.
(1) Hydraulic turbines convert the potential energy of water into shaft work, which, in turn, rotates the electric generator coupled to it in producing electric power. Pelton turbine named after Lester Allen Pelton of the USA, an impulse turbine used for high head and low discharge. In an impulse turbine all the available head of water is converted into kinetic energy in a nozzle. The water shoots out of the nozzle in a free jet into a bucket which revolves...
In an impulse turbine of the Pelton type, the jet is turned by the bucket by 165°. The head available at the nozzle is 750 m and blade speed ratio is 0.46. Cv = 0.98. Relative velocity is reduced by 12% due to friction. Determine the hydraulic efficiency. If the flow available is 20 m3/s. What is the power potential. Assuming 5 units of equal power, determine the jet diameter and wheel diameter if d/D = 12.
Water under a head of 300 m is available for a hydel-plant situated at a distance of 2.35 km from the source. The frictional losses of energy for transporting water is equivalent to 26 m. A number of Pelton wheels are to be installed generating a total output of 18 MW. Determine the number of units to be installed, diameter of Pelton wheel and the jet diameter when the following data are available: Wheel speed 650 rpm.; ratio of bucket...
At a site the head available is 315 m and the maximum power potential is 35 MW. If the dimensionless specific speed is to be in the range 0.015 to 0.02 determine the number of units required and the power of each unit. If the overall efficiency is expected to be 85%, determine the flow rate. If Cv = 0.97 and φ=0.46, determine the speed if the wheel diameter is 10 times the jet diameter. edit: impulse turbine (pelton turbine)...
3) (35 points) A Francis turbine operates at its maximum efficiency point at nH-0.94, corresponding to a power specific speed (eq.9.1) of 0.9 rad. The effective head, HE, across the turbine is 160 m and the speed required for electrical generation is 750 rpm. The runner tip speed is 0.7 times the spouting velocity, co 2gHg, the absolute flow angle at runner entry is 72° from the radial direction, and the absolute flow at runner exit is without swirl. Determine:...