Question

If 0.1 g of Ferric sulfate Fe_2(SO_4)_3 is added to 1 L of water, Express the concentration of Ferric sulfate in the following in terms of (a) mg/L, (b) ppm, (c) molarity, (d) % weight (Assume the specific gravity of solution is 1.0) A 10-litre cylinder containing 500 g of chlorine gas is to be used for disinfection of water. What will be the pressure inside the cylinder at a temperature of 20 degree C? A digester gas holding tank with floating top contains 10,000 m^3. During the night, the temperature of the gas is 10 degree C, which warms up to 27 degree C during the day time. Assuming that no gas is used and the pressure inside the tank remains constant, what volume will the tank have at 27 degree C? Five liters of water are equilibrated with gas mixture containing carbon dioxide at a partial pressure of 0.3 atm. If the Henry's law constant for carbon dioxide solubility is 31.6 atm-L/mol, at 25 degree C how many grams of carbon dioxide are dissolved in the water? In each case, which bond is more polar? a) B - Cl or C - Cl b) P - ForP - Cl

Answer 1

1) Ferric Sulphate Mol wt = 400

Mass of ferric sulfate = 0.1 gms

No of moles = 0.1/400 = 0.00025

Therefore Molarity = 0.00025 M

100 mg/L or 100 ppm

0.01%

2) PV=nRT

V= 10 L, T= 293.15K, n= 500/70.906 (7.05 moles), R=0.0821 atm L mol-1 K-1

P = 7.05*0.0821*293.15/10

P= 16.97 atm

3) V1/T1 = V2/T2 (n,p constant)

10000/283.15 = X/300.15

Therefore X = 10600.39 m3

5) a) E.N of B = 2

E.N of C = 2.5

E.N of Cl = 3

Since E.N difference between B-Cl is more, it is more polar

b) E.N of P = 2.2

E.N of F = 4

E.N of Cl = 3

Since E.N difference in P-F is more it is more polar