Question

d B P R (a)The bar shown in the figure has the diameter of 80 mm and made of aluminum. The allowable stress for tension is 90 MPa and the allowable shear stress is 50 MPa for the aluminum. Take ? = 320 mm, ? = 0.2? N.m and ? = 20? N.

Determine the state of stress at points A and B and sketch the results on differential elements located at these points.

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Answer #1

due to P = 20RN tensile streyes produce 20R at A Il 0.00397R Mpa xx=1 17 17.30 at B oxx = 7 +0.00397 R MPa due to Torsion loabenging moment Ry 320 320RN Noming INA CL at B - to = + 32oR xx x 40 4 (80) 64 11 0.006366R mpa at 사 = 6T 3 x = омра I so finstate of strey condition at B Oxx = t 0.00397R+ 0.006366R = 0.010336R mpa тх 1 0.00 198 R Mpa TxY -0.000198 R Mpa I 0.00198R

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