A solid lead sphere of radius 10 m (about 66 feet across!) has a mass of about 57 million kg. If two of these spheres are floating right next to each other (centers 20 m apart) in deep space, the gravitational attraction between the spheres is only 540 N (about 100 pounds). How large would this gravitational force be if the distance between the centers of the two spheres were doubled?
here,
mass , m = 57 Mkg
radius of the lead sphere , r = 10 m
distance between the sphere , d = 20 m
force when d= 20 m , F = 540 N
when dnew = 2 * d
dnew = 40 m
let the new force be Fnew
using gravitation law
Fnew / F = (d/dnew)^2
Fnew = 540 * (20/40)^2
Fnew = 135 N
gravitational force when the distance between the centers of the two spheres is doubled is 135 N
A solid lead sphere of radius 10 m (about 66 feet across!) has a mass of...
A solid lead sphere of radius 10 m (about 66 feet across!) has a mass of about 57 million kg. If two of these spheres are floating right next to each other (centers 20 m apart) in deep space, the gravitational attraction between the spheres is only 540 N (about 100 pounds). How large would this gravitational force be if the distance between the centers of the two spheres were doubled???? please and thank you!!
A solid lead sphere of radius10 m about 66 ft across has a mass of about 57 million kg if two of these spheres are floating in deep space with the centers 20 m apart the gravitational attraction between the spheres is only 540 N (about 120 lb) then how large would the gravitational force be if the distance between the centers of the two spheres were tripled?
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