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If a particle with mass m moves with position ! r(t), then, the angular momentum is...

If a particle with mass m moves with position ! r(t), then, the angular momentum is defined as ! L(t) = m! r(t) × ! v (t) and its torque is ! τ (t) = m! r(t) × ! a(t). Show that ! L′(t) = ! τ (t) . What are the consequences for both ! a(t) and ! L(t) when ! τ (t) = ! 0 for all t?

THIS IS CALC 3 VECTOR STUFF MUST USE CALCULUS

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The position of particles is r (t)-M+,jtzk , where ijk represent the unit vectors along x, y, z directions respectively. v(t)

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