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Tutorial: Angular Momentum and Torque III. Angular Momentum The angular momentum of a point particle is defined by: L = ixp.
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at position of the airplane is drawn below.direction of angular momentum of the airplane is given by cross product of position vector and momentum vector of airplane i.then thumb point in the direction of angular momentum. Direction of angular momentum will be upward as shown by green colour.If top view is taken as below momentum vector position Vector ? , angular momentum vector (pespeneliceby to plane of paper) (90° This is shown with blue colour. momentum vector position vector 909 Xa angular te momentum vector (pespeneliceday to planiv) magnitude of angular momentum of the airplane \Ž=\PxP L=rpsin 0 L=rmvsin 0 Substitute r= a and A = 90° L = amvsin 90° L=mLI * - - - - ----> E E 11 momentum vector will be in the velocity vector. | 0--------------- l to Draw vector d B.)Direction of angular momentum will be out of the page, perpendicular to plane of paper outward as shown by green colour. OzgoL=(d) x (mv) (sin 90°) L=mvd T is drawn below. 30°C m 1 1> from triangle ABCr= 2d The angle between linear momentum of the particle and can be calculated (make same origin)Direction of m O=30 direction of a 0 = 30° iii) Direction of angular momentum of the particle will be out of the page, perpen30° nec 1 el m 1> magnitude of angular momentum of the particle is Ž[=]; xp | L=rpsin e L=rmysin e L=(2d) x (mv) * (sin30°) L

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