Question

Example : On a single cylinder reciprocating machine, stroke 20 cm, connecting rod length 30 cm, connecting rod mass 3 kg, piston mass 2 kg, piston diameter 20 cm, crankshaft speed 3000 rpm, friction coefficient between cylinder and piston 0.5 and the connecting rod mass center is 10 cm from the center of the crankshaft. What is the pressure of the piston that will make the torque coming to the crankshaft 425 mN in the clockwise direction when the crank passes the External Dead Point by 37 degrees? (Rotational masses are balanced.) cos 20 sin 20 V=-ro sin + 2n a=-ro' cos + -roºf cos 0=ot, n=-%= tan-u n 7

Answer 1

Solution eo Ralius of weank e = strone 2 20 = 10 cm = 0.1 m .n l to zo 3 IO 0 ® 37 3. sind sino п sin 37 3 = 11:57 Given, Tocque (): 425 Nh A = T= ft x L Fp sinlo+0) X & Cos fe x sin (37 +11.57) Xo. => 425 = cos 11:57 (Piston e Hote) fp= 5553:264 N fp = fl-Fatong -

fi EL An d² x P A4 (0.2) 2 xp 0.03 14 P. Р d 20cm = 0.2 m Pęessure diameter og piston FI mw?ų (coso + Co2 20 5X6314) 2 (0.1(cos us 3.7 + Cos (2237) FI Xo.1 3 43900. 59 N (m= totul mess of seeipeculing part w 3+2 ZANIGO 27x3000 GO 314 Eeod 15 Now, fot vechi ceel engine 5553.264 = 0.0314 P – 4 3900.59 +5498) Р 1.573 X10 Po 1.573 Mpg 1573 kPa G Pressure on piston (P) =1573 kry -Xox