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Part XI 71. 2 Mn04. (aq) + 5C2042-(aq) + 16H+(aq) → 2 Mn2+ (aq) + 10CO2 (g) + 8H20(1) Permanganate and oxalate ions react in an acidified solution according to the balanced equation above. How many moles Mn2(g) are produced when 20. mL of acidified 0.20 M KMnO, solution are added to 50. mL of 0.10 M Na,C,o.? a) 0.0020 mol b) 0.0040 mol c) 0.0090 mol d) 0.010 mol
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2 5 gaven 3 So-- moles mnhope this is helpful.

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Part XI 71. 2 Mn04. (aq) + 5C2042-(aq) + 16H+(aq) → 2 Mn2+ (aq) + 10CO2...
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