Question

5 mm mm 0.5 mm 1.- 3.04 2.0 100 x X X

calculate the magnification of fields 1 and 3, and the field diameter of 2 . (hint. Use your ruler.) Note the the numbers for the field diameters below are too large to represent the typical compound microscope lens system, but the relationships depicted are accurate

Answer 1

For a microscope

$m\times d=constant$..........(1)

With m = magnification of microscope

d= diameter of field of view

Given for field 1

$\\d_1=5mm\\\ m_1=?$

For field 2

$\\d_2=?\\\ m_2=100$

For field 3

d3 0.5тт т3 =?

therefore from equation (1)

$\\m_1d_1=m_2d_2\\and \\ m_2d_2=m_3d_3$

Put the values from above we get

$\\m_1\times 5=100\times d_2\\and \\ 100\times d_2=m_3\times 0.5$

Or

$\\m_1=20d_2\\and \\ m_3=200d_2$

Now from figure we can see

So let's choose $d_2=2.5mm$

Therefore From above equation

$\\m_1=20\times 2.5=50\\and \\ m_3=200\times 2.5=500$

Therefore for field diameter=2.5mm of #2

Magnification for field #1 and #3 are 50 and 500 respectively.

Similarly you can choose other possible value of $d_2$ as per your ruler

And correspondingly magnification of field 1 and 3.