4. 120 POINTS = 10 + 101 USE THE SAME SUMMARIES BASED ON THE SAMPLE OF...
2. [25 POINTS = 15+101 BONNIE (WHO WORKS AS INSURANCE ANALYST) COLLECTED DATA FOR TWO INDEPENDENT GROUPS OF CAR POLICIES, EACH GROUPS INCLUDED n1 = n2 8 MONTHLY PREMIUM VALUES. BONNIE ASSUMED THAT THE POPULATION VARIANCES FOR TWO GROUPS ARE KNOWN AS (σ)-(o2)2 = 9 SAMPLE SUMMARIES WERE FOUND AS FOLLOWS (SAMPLE MEAN FOR GROUP I) = 33.40 AND (SAMPLE VARIANCE) = 7 (SAMPLE MEAN FOR GROUP II)-37.30 AND (SAMPLE VARIANCE)-11 AT THE 1% SIGNIFICANCE LEVEL, DOES BONNIE HAVE SUFFICIENT...
Construct a 95% confidence interval to estimate the population mean with x=101 and σ=27 for the following sample sizes. a) n equals= 3030 b) n equals= 4343 c) n equals= 6464 a) With 95% confidence, when n=30, the population mean is between the lower limit of and the upper limit of. (Round to two decimal places as needed.) b) With95% confidence, when n=43, the population mean is between the lower limit of and the upper limit of. (Round to two...
Below are numerical and graphical summaries of Price. Use these to complete Questions 7 and 8. Descriptives Statistic Std. Error price Mean 80.7500 4.98105 95% Confidence Interval Lower Bound 70.8355 for Mean Upper Bound 90.6645 Median 73.9750 Variance 1984.867 Std. Deviation 44.55184 Minimum 9.99 Maximum 249.00 Range 239.01 Interquartile Range 47.29 Frequency 25 50 75 175 200 225 250 100 125 150 price 7. Consider the variable Price. A. Complete the table below. Mean Median Standard deviation Sample size B....
INFERENCES ABOUT THE POPULATION MEAN DISTINGUISH BETWEEN Z-TEST AND T-TEST. 1. A GROUP OF 9 STORE MANAGERS WAS DRAWN FOR ANALYSIS OF THEIR IQ SCORES. ASSUME THAT INDIVIDUAL SCORES ARE NORMALLY DISTRIBUTED, WITH THE UNKNOWN POPULATION AVERAGE AND POPULATION STANDARD DEVIATION OF 15. SAMPLE SUMMARIES WERE: (SAMPLE MEAN) = 88.2 AND (SAMPLE STANDARD DEVIATION) = 12. (A) AT THE 1% SIGNIFICANCE LEVEL, DO WE HAVE SUFFICIENT EVIDENCE THAT THE POPULATION AVERAGE IQ WAS BELOW 100? CIRCLE ONE: YES! || NO!...
A random sample of 34 observations is used to estimate the population mean. The sample mean is 104.6 and the sample standard deviation is 28.8. What is the Upper Confidence Limit for a 95% confidence interval for the population mean? Round your answer to 1 decimal place.
QUESTION 12 A sample of size 100 is chosen from a population. The sample mean is 100 and the standard deviation is 15. Find the upper limit of the 95% confidence interval for the population mean. Round off to three decimal places
Construct a 95% confidence interval to estimate the population mean with x overbar =118 and sigma =32 for the following sample sizes. a) n = 32 b) n = 43 c) n = 65 a) With 95% confidence, when n=32, the population mean is between the lower limit of ___ and the upper limit of ___. (Round to two decimal places as needed.) b) With 95% confidence, when n=43, the population mean is between the lower limit of...
Question 1 Suppose S is the sample variance based on a sample size n from a normal population with unknown mean and variance. Derive a 100(1-a)% a) upper confidence bound for o?. b) lower confidence bound for o?. c) Arik the astronaut decides to prepare for his upcoming trip by experimenting with homemade rockets (using Alka-Seltzer tablets and water to launch them into the air)! He wants to understand the variability of peak height for his rocket design so he...
10) Suppose that you are asked to use a sample of size 50 to create a 95% confidence interval for a population mean. The lower limit of your interval turns out to be L and the upper limit turns out to be U. If you were to change the confidence level to 90% and use the same sample data to create a revised confidence interval, would it be correct to say that the revised interval would have a lower limit...
We draw a random sample of size 25 from a normal population with a known variance of 2.4. If the sample mean is 12.5, what is the Lower Confidence Limit for the 95% confidence interval for the population mean? Include 1 decimal place in your answer