Q1.
At x = 10
z = (x - average completion time)/Standard deviation
or, z = (10-15)/3 = -1.67
At x = 12
z = (12-15)/3 = -1
Probabilities of task completing between 10 and 12 minutes = P(-1.67<z<-1)
= P(z<-1) - P(z<-1.67)
= 0.1587 - 0.0475
= 0.1112
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