Question
Please be clear and answer everything in the question and show every step and where you got any data/number otherwise don’t answer it

Use two failure criteria (two different criterions for each material) to find safety factors for the following materials with the plane stress state shown in Figure 1. (a) 1018 hot rolled steel (b) ASTM 35 gray cast iron y50 MPa y,-40 MPa ух Try 40 MPa x 100 MPa 100 MPa 50 MPa
0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
Please be clear and answer everything in the question and show every step and where you...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • step by step please. A ductile hot rolled steel bar has minimum yield strength of 360...

    step by step please. A ductile hot rolled steel bar has minimum yield strength of 360 MPa. Using the distortion-energy and maximum-shear-stress theories, determine the factors of safety for the following plane stress states: (20 points) (a) 0x = 200 MPa, y = 120 MPa (b) x = 180 MPa, Txy = 150 MPa (c) Txy = 100 MPa

  • Draw the not-yielding envelope of MSS and DE theory, and then show all the load lines....

    Draw the not-yielding envelope of MSS and DE theory, and then show all the load lines. Please show the yield strength data in your graph along with other data. You need to use free-hand-sketch to draw the DE based envelope. A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of 350 MPa Using the distortion-energy and maximum-shear-stress theories determine the factors of safety for the following plane stress states (a) 100 MPa, a, = 100...

  • Please complete all of #6 :) your result to that from the previous step). 6. Repeat...

    Please complete all of #6 :) your result to that from the previous step). 6. Repeat the previous problem. This time, the stress state is oz = 10 ksi, oy = - 20 ksi. 7 Gray cast iron with an ultimate tensile strength of 31 lei and an ultimate com 5. It has been determined that the critical stress in a part under a certain load is given by 0r = 10 ksi and oy = 20 ksi. The part...

  • please show clear working and box and label each answer! thank you The figure illustrates the...

    please show clear working and box and label each answer! thank you The figure illustrates the nonpermanent connection of a steel cylinder head to a grade 30 cast-iron pressure vessel using N bolts. A confined gasket seal has an effective sealing diameter D. The cylinder stores gas at a maximum pressure Pg For the specifications given in the table for the specific problem assigned, select a suitable bolt length, assuming bolts are available in increments of 5 mm. Then determine...

  • answer question 2 please A material may fail in many ways; in a ductile or brittle...

    answer question 2 please A material may fail in many ways; in a ductile or brittle mode; by creep or fatigue; by corrosion or stress corrosion; by hydrogen or liquid metal embrittlement; by slow tensile overload or by impact. An examination of the failure may tell you a lot about the material and the failure mode. In this course, you have learned (we trust) the correlations between structure-properties, - applications. This leads to material selection. However, the engineer has to...

  • Please show all working clearly and box and label each answer. thank you The figure illustrates...

    Please show all working clearly and box and label each answer. thank you The figure illustrates the nonpermanent connection of a steel cylinder head to a grade 30 cast-iron pressure vessel using N bolts. A confined gasket seal has an effective sealing diameter D. The cylinder stores gas at a maximum pressure Pg For the specifications given in the table for the specific problem assigned, select a suitable bolt length, assuming bolts are available in increments of 5 mm. Then...

  • help with question 4 please. there are two samples given with two different pictures of each...

    help with question 4 please. there are two samples given with two different pictures of each A material may fail in many ways; in a ductile or brittle mode; by creep or fatigue; by corrosion or stress corrosion; by hydrogen or liquid metal embrittlement; by slow tensile overload or by impact. An examination of the failure may tell you a lot about the material and the failure mode. In this course, you have learned (we trust) the correlations between structure-properties,...

  • help with question 5 please. there are two samples given with two different pictures of each....

    help with question 5 please. there are two samples given with two different pictures of each. all of the information to solve is given A material may fail in many ways; in a ductile or brittle mode; by creep or fatigue; by corrosion or stress corrosion; by hydrogen or liquid metal embrittlement; by slow tensile overload or by impact. An examination of the failure may tell you a lot about the material and the failure mode. In this course, you...

  • hep with question 3 please A material may fail in many ways; in a ductile or...

    hep with question 3 please A material may fail in many ways; in a ductile or brittle mode; by creep or fatigue; by corrosion or stress corrosion; by hydrogen or liquid metal embrittlement; by slow tensile overload or by impact. An examination of the failure may tell you a lot about the material and the failure mode. In this course, you have learned (we trust) the correlations between structure-properties, - applications. This leads to material selection. However, the engineer has...

  • Could someone please tell me why max stress goes to zero in this answer. YIELDING CRITERIA...

    Could someone please tell me why max stress goes to zero in this answer. YIELDING CRITERIA FOR DUCTILE MATERIAL - EXAMPLE 1.1 0=+ *29) +=54.500 + |(40240) + z = . =-00+78 100 MPa 10x - 0 Ob = Ox toy 2 * 2) + Tžy - On = -00-00 2 17-00+ 0 / 2 -> 00= -00 – Txy - 2 ] + Try / 0o = 200 MPa = -100 MPa Oa = -00 + Txy Oq =...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT