Given the value Ka of HF is 6.6x10^-4, write an equilibrium
equation for the reaction in water of the following and calculate
the pH for:
a) .100 M HF
b) .100 M NaF
Given the value Ka of HF is 6.6x10^-4, write an equilibrium equation for the reaction in...
3. A solution is prepared by treating 50 mL of 0.50 M HF (Ka = 6.6x10 ) with 10 mL of 1.15 M NaOH. Calculate the pH of the solution. 4. If enough NaOH is added to the solution in problem 3 to neutralize the HF, what will the pH be? 5. 42.16 mL of a solution of NaOH are required to neutralize 0.7878 g of potassium hydrogen phthalate (Mwt = 204.23 g/mol). Calculate the molar concentration of NaOH in...
Calculate the pH of a 0.10-M solution of sodium fluoride (NaF) at 25°C. Ka (HF) = 6.6x10^-4 (Please explain all steps and reasoning)
For a 0.7M HF solution with a Ka= 6.6x10-4 What is the H30+ concentration: Whats id the pH:
a) write the net ionic equation for the reaction between HF(aq) and NaO(aq). determine if the value of the equilibrium constant for this reaction b) would the volume of 1.0M NaOH solution needed to completely neutralize 25mL of a .5M HF(aq) be greater than less than or equal to the volume of 1.0M NaOH needed to neutralize 25mL of .5M HClO4 (aq) c) after all the HF is neutralized by the NaOH would the pH of the resulting solution be...
4. What is the value (M) of [H3O+] of a solution with pH = 2.0 ? State the given and needed quantities, write the proper equation. Substitute values into the equation and calculate. 5. Which of the following could be a buffer? In general what is the function of a buffer? Explain with a second example. A) NaF(aq) B) HF(aq) + NaF(aq) C) HF(aq) + O(l) D) NaF(aq) + O(l) E) NaCl(aq) + HF(aq)
Calculate the pH of a 3.51×10-3 M solution of NaF, given that the Ka of HF = 6.80 x 10-4 at 25°C.
Calculate the pH of a 3.27×10-3 M solution of NaF, given that the Ka of HF = 6.80 x 10-4 at 25°C.
a)What is the kb for F- given that the ka for HF is 6.8*10-4. b)What is the pH of a 0.379 M solution of NaF? i just really need part b. i have part a.
1. Write the balanced chemical equation for the reaction of HF with water. Type your answer here. 2. What is the pH and concentration of F– in a 0.100M solution of HF? Ans. pH = 2.10 Insert your work image here. 3. Write the balanced chemical equation for the dissolution of NaF in water. Type your answer here. 4. What would happen if the equilibrium [F–] that you calculated in 2 was changed by adding 0.00500 moles of solid NaF to...
Calculate the equilibrium concentrations and pH of the following: a) 0.58 M HF (Ka=6.8x10^-4) b)0.75 M NH3 (Kb=1.76x10^-5)