Question

10 G(S) 52 + 7s + 10

With an amplitude of 10 using a step input function what will the open loop steady state error?

0, 2, 5, or 10?

Where would the zero be located if a PD controller is used and a desired rise time of 260 ms and percent overshoot of 5% is desired?

-40, -30, -25, -20

The plant is then modified so that G(s) = .95(s+15) with a step function input of amplitude 2, what will the static error coefficient be?

unity (1), 28, 14, or none of the available

The system is modified again with a static error coefficient of 10 and input step amplitude of 5 what will the steady error be?

0.09, 0.1, 0.45, not enough information

From all of the information gathered the PD controller will now run with a static error of 9 and steady state of 0.15 with a unit step response. Using a lag controller to alter the error to 0.05 with a pole of -.5 what is the zero location ?

-1.056, -1.5, -2.11, not enough info

0 0
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Answer #1

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