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4. 80.00 ml of 0.125M methylamine solution (HiCNH2, pKa for H,CNH,- 10.632) is titrated with 0.100 M solution of HNOs. Find the pH at the following points. (30 points). a- Before the addition of any HNO3. b- After the addition of 50.00mL of HNOs solution. c- After the addition of 70.00 mL of HNOs solution. d- After the addition of 100.00 mL of HNOs solution e- After addition of 125.00 mL of HNO: solution. f- At what volume of added HNOswill poH pKb
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4@)Bo addiian st any HNO ナ7( ナχ ha 2 33 X10-1 0125- a kbu small 0 126-10 125 0.125(2 01X10-2) 8 PMs. 14-port-一14-168-12-32 200 moles H3CNH2-0-125x80 no.el mdes sL HNO2 0.1 x50 5mmoles 3 5 5 Tolal Volume 80HCN21 5-0.0385M 130 13 o 3.368 + og 0 0385 O 038 5 он-3.368. po PHa4 POH 14-3 36810 632 Allo +the a 3 HNO こ 1 mmoles OddyT lo Total-Volum 1 80 +10: 150 mL H2 13 0.02 15o 15 O 3 368 CH3 CNH2 kag 0046 3.13 10 mmoles180 equivalinu paint au 2t lo10 632 2- Co o56-1) 212. O 056-2 a-33 x 10-11.- 33 x1012 o o56 1.143.xto-G-一 二 Oddumoles okHNO3 01x125 ag C0 0122) ot at 50mL about rim (b) paut

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80.00 ml of 0.125M methylamine solution (H_3 CNH_2, pKa for H_3 CNH_3^+1 = 10 632) is...
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