Question

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Problem 5 - A car air conditioner takes in outside air at 32'C with relative humidity of 95%. The air is conditioned to 24'C and 60% humidity after passing over the working fluid coils. The system can be approximated with the diagram below. Determine the amount of cooling [kj] required and the amount of water removed (kg) per 1000m of dry air processed. Cooling coils lllllllllllll 0.06 T, = 24°C 62 =60% T = 32°C =95% 0,00 OD 1 atm Condensate 28°c Condensate removal

Answer 1

J W Caraming of coy an). OU DBT) 24°C 32° from psychrometorić chast, At outside, ( 32°C, 95% RH) hi = 106.49 kJ/kg of day aus W, = 0.02904 kg/kg of doy aur V = 0.9038 m / kg Volume of and = 1000m3 mass of avi a me Volume Speutic volume = 1000 0.9038 ma = 1106.43 kg Conditioned out, (24°C , 604.RH). h2 = 52-61 kJ/kg of doy air Uz = 0.01119 kg 1 kg of aby air

The condensate leaves at 28°C, hwa hf@ 28€ = 117.4-Ktikg Applying energy balance and mass balona, É mw,i = É mw, o maio, = mas wat in w mw = mia (wi_W2) | By = 1106.43 (0.02904-0.01119) Iniw = 19.75 kg ] energy balance, E - $ E - EDM+= AE con Ein = Eout Asylum 20 Émihi - Qout tĖmene. Qout = mashi-(maszt n'whw) =ma, Chi-hz)-m who = 1106.43(10649-52.61)–19.75 x 117.4 | Pont = 57296.3 kJ |