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28 ΚΩ 4 ΚΩ ΚΩ 9 ΚΩ Ideal -11V 3 12 ΚΩ (*) 1.6V Given: The operational amplifier in the above circuit may be considered ideal.

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Answer #1

28kr 4ka 1.6V 116 WM 4kn + Vo 3 12KR 1.6V 1 Apply kcl (kirchoffs current law) at node @ 0-1.6 1.6-41 4K 28k -1.6 = 1:6-VI -1

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