the solobulility of bacro4 (s) in water is 3.7 milligrams in 1.0 L at 25 C...
the solobulility of bacro4 (s) in water is 3.7 milligrams in 1.0 L at 25 C calculate the value of ksp for bacro4
Homework Answers
A) Ksp = [Ba++][CrO4--]
solobulility of bacro4 (s) in water is 3.7 milligrams in 1.0 L =
3.7 * 10^-3 M
For every x moles of BaCrO4 that dissolves in a liter of water, the
concentration of Ba++ is x Molar, and the concentration of CrO4--
is x Molar. Therefore,
Ksp = (x)(x) = x² = (3.7 x 10^-3 M)² = 1.369 x 10^-5
M².
You are given mg. Convert mg to mol. 3.7mg / molar mass of BaCrO4. Then square the answer, 2.1x10^-10.
Add Answer to:
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