The value of Ksp for TlCl(s) in equilibrium with water at 25°C is 1.9 × 10−4...

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The value of Ksp for TlCl(s) in equilibrium with water at 25°C is 1.9 × 10−4...

The value of Ksp for TlCl(s) in equilibrium with water at 25°C is 1.9 × 10−4 M2. Write the chemical equation that represents the solubility equilibrium for TlCl(s) and calculate its solubility in grams per liter
in water at 25°C.

science chemistry

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Answer 1

Answer #1

TlCl(s) -------------> Tl^+(aq) + Cl^-(aq)

---------------------- x -------------- x

Ksp = [Ti^+][Cl^-]

1.9*10^-4 = x*x

x^2 = 1.9*10^-4

x = 0.013784

solubility of TlCl = 0.013784mole/L

molar mass of TlCl = 239.82g/mole

solubility of TlCl = 0.013784mole/L * 239.82g/mole

= 3.3056g/L >>>>answer

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Answer 2

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