Homework Answers
Solution-
We have ksp of CaSO4 = 3.0*10^-5
The reaction can be written as
CaSO4 ---------> Ca+2(aq) + SO4-2(aq)
s s
Ksp = [Ca+2] [SO4-2]
= (s)*(s)
=>3.0*10^-5 = s^2
=>s= 5.48*10^-3 M
Molar mass of CaSo4 = 136 g/mol
THerefore the solubility= (5.48*10^-3)*(136)
= 0.745 g/l
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