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6 Points You are to throw six dice simultaneously and observe the topside of each die. Q1.1 3 Points What is the probability
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Answer #1

We throw six dices simultaneously, and we observe the topside of each die.

We have to find the probability of getting a triple pair.

Now, if we throw six dice, then each can have 6 outcomes.

So, the number of all possible cases is

6^{6}

Now, first we choose which throws would make the pairs.

This can be done in

\frac{6!}{2!2!2!}

ways.

The first pair can have 6 outcomes. The second pair can have 5 outcomes. The third pair can have 4 outcomes.

So, the number of favourable cases is

=\frac{6!}{2!2!2!}*6*5*4

So, the required probability is

=\frac{\frac{6!}{2!2!2!}*6*5*4}{6^{6}}

=0.3086

So, the answer is 0.3086.

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