(use TUKEY for the multiple
comparisons)
Solution:
SAS CODE:
data cholesterol;
infile cards;
input treat $ cholvalues;
cards;
A 220
A 190
A 180
A 185
A 210
A 170
A 178
A 200
A 177
A 189
B 160
B 168
B 178
B 200
B 172
B 155
B 159
B 167
B 185
B 199
placebo 240
placebo 220
placebo 246
placebo 244
placebo 198
placebo 238
placebo 277
placebo 255
placebo 190
placebo 188
;
run;
proc anova data=cholesterol;
class treat;
model cholvalues = treat;
means treat / tukey cldiff ;
run;
output:
The ANOVA Procedure | |||||
Dependent Variable: cholvalues | |||||
Source | DF | Sum of Squares | Mean Square | F Value | Pr > F |
Model | 2 | 16258.47 | 8129.233 | 17.58 | <.0001 |
Error | 27 | 12483.4 | 462.3482 | ||
Corrected Total | 29 | 28741.87 |
From ANOVA table
F(2,27)=17.58
p<0.0001
p<0.05
Reject H0
there is sufficient statistical evidence at 5% level of significance to conclude that all the 3 group means are different.
The ANOVA Procedure | ||||
Tukey's Studentized Range (HSD) Test for cholvalues | ||||
Note:This test controls the Type I experimentwise error rate. |
||||
Alpha | 0.05 | |||
Error Degrees of Freedom | 27 | |||
Error Mean Square | 462.3481 | |||
Critical Value of Studentized Range | 3.50633 | |||
Minimum Significant Difference | 23.842 | |||
Comparisons significant at the 0.05 level are indicated by ***. | ||||
treat | Difference | Simultaneous 95% Confidence Limits | ||
Comparison | Between | |||
Means | ||||
placebo - A | 39.7 | 15.858 | 63.542 | *** |
placebo - B | 55.3 | 31.458 | 79.142 | *** |
A - placebo | -39.7 | -63.542 | -15.858 | *** |
A - B | 15.6 | -8.242 | 39.442 | |
B - placebo | -55.3 | -79.142 | -31.458 | *** |
B - A | -15.6 | -39.442 | 8.242 |
from tukey paiwise comparsions
A - placebo |
B - placebo |
are different
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