Question

5. A particle of mass 2.00 mg and charge-6.00 ?C travels with horizontal velocity v - 230 m/s. The particle enters a region with vertical electric field, travels through the field and exits at a direction of 35.0° below the horizontal. Find the potential difference between the points where the particle entered and exited the electric field

Answer: 4320 V

Please show all steps with pictures pls! Thanks

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