Question
can you pls help me identifiy the correct unknown ans explain why this is the know for the unknown its not 2phenylethanol.
Melting point of solid (C) (leave blank if liquid at RT): 57 degrees Celsius Boiling point of liquid (C) (leave blank if sol
Differentiate halogen ion test no halogen The results of unsaturation tests and ignition test for aromaticity Predicted color
Lucas test solution cloudiness Chromic acid test solution blue green The derivative for your compound and the melting point o

halogens is absent, differntiate is absent , nitrogen test is absent, sulfure is absent, Br2 is absent, kmno4 absent, ignition test absent . 2,3 dnp contains ketone ,tollens no aldehdye absent aldehyde , iodoform test contains carbonyl in it .

1 APPENDIX 1 20 YOU Tables of Unknowns and Derivatives More extensive tables of unknowns may be found in Z. Rappoport, ed. Ha
APPENDIX 1 Tables of Unknowns and Derivatives ALDEHYDES (Cont.) X1039A 2,4-Dinitro- Semi- phenyl- carbazone hydrazone* BP MP
KETONES (Cont.) APPENDIX 1 Tales of Unknown and Derivatives 987 2,4-Dinitro- phenyl- hydrazone BP Semi- carbazone MP 176 187
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Answer #1

From the Given tests,it can be clearly concluded that the given compound contains :

i) No special element

ii) Aromatic moiety

iii) Alcohol Group (as evident from the IR spectrum at the broad band from 3100-3600 cm.-1). Also confirmed from Cerric Chloride test.

iv) The Alcohol is Primary, as evident from the Lucas Test.

Hence, it can be clearly concluded that the Compound is an Aromatic Primary Alcohol. But, I couldn't identify the Compound, as you hadn't given any melting point chart for Alcohol. Please find an Aromatic Primary Alcohol in the melting point chart, whose melting point is ~57°C

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