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1) CH30Na, CH30H H3CH2C, H3C CH. 2) H30 OH OH OH OH HO CH HO CH3 HO CHa HO CH3 OCH OCH OCH OCH Haco CH H3CO CH HaCO Haco CH CH3 OH OH OH OH H3CO CHa H3CO CH3 H3CO CH H3CO CH OCHa OCH OCH OCH HO CHa HO CH3 HO CH3 HO CH3 Look at the given reaction and use the letter code corresponding to each compound in the blank to indicate the expected product(s), or fill in the blank with the appropriate vocabulary word or phrase. If a specific stereoisomer (e.g single enantiomer) is formed, select that isomer only. If a mixture of stereoisomers (e.g. racemic or diastereomers) is formed, select the single structure that shows the appropriate mixture (e.g. lines not dashes). The specific functional group in the starting material is a(n) group. a The product of this reaction is compound mechanism at the (more/less) substituted side of the ring. If we convert the reagents to H2SO4 and CH30H the major product will be compound a mechanism at the (more/less) substituted side of the ring. f we convert the reagents to 1) H20, NaOH and 2) H30 the major product will be compound This is a(n) (name of reaction

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Answer #1

The specific functional group in starting material is epoxide group. The product of the reaction is N via SN2 mechanism at less substituted side of the ring.

If we convert the reagents to H2SO4 and CH3OH the major produt will be compound L by a SN2 mechanism at more substituted side of te ring.

If we convert the reagents to 1) H2O, NaOH and 2) H3O+ the major product will be compound B. This is an SN2 reaction.ey 仆 0) 히) ol)

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