A solenoid is wound with a single layer of insulated copper wire of diameter 3.000 mm and has a diameter of 3.000 cm and is 1.800 m long. Assume that adjacent wires touch and that insulation thickness is negligible.
1. How many turns are on the solenoid?
2. What is the inductance per meter (H/m) for the solenoid near its center?
1] Number of turns x diameter of the wire = length of the solenoid
=> N (3 x 10-3) = 1.8
=> N = 600 turns
2]
Inductance is given by:
=>
= 0.7106 mH.
so, Inductance per meter will be: L/1.8 = 0.395 mH.
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