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Consider the following LP problem. minimize 3:01 +4.c3 subject to 2:01 + x3 - I3 < -2 21 +3.02 – 5x3 = 7 21 <0,22 > 0, 03 fre

maximize -2p1 + 7p2 subject to 2p. + P23 1 + 3p2 50 -P1 - 5p2 = 4 Vi < 0,2 > 0 maximize --2p1 + 702 subject to 2p. + P23 1 +

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Standard krimal problem Minimize 34+ 403 sit 2x+2, ₂5-2 x +39-543 3,7 D 450, R30 x free Its dual is Maxibatzea Maximize, 2 b

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