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A 50-kg sledder is sliding North on a large frozen lake at 2 m/s, when a...

A 50-kg sledder is sliding North on a large frozen lake at 2 m/s, when a 30-s gust of wind from East to West blows her off course. 90 s after the wind stops (two minutes after the start of the journey), the sledder is 339.4 m North-West of her initial position (when the wind started).

If the sledder gets no other pushes other than the wind and just slides freely otherwise during the two minutes, what was the magnitude of the average force exerted on her by the wind? (2 s.f.)

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Answer #1

Impulse J = force* time = change in momentun

so

F t = Mv

force F = MV/t


F = (50 * 2)/(120)

F = 0.834 N

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