Question

When a falling meteoroid is at a distance above the Earth's surface of 3.20 times the Earth's radius, what is its acceleration due to the Earth's gravitation?
_______ m/s² towards earth

Answer 1

Gravitational constant = G

Mass of Earth = M

Radius of Earth = R

Gravitational acceleration at the Earth's surface = g = 9.81 m/s²

GM R2

Distance of the meteoroid from the Earth's surface = H = 3.2R

Distance of the meteoroid from the Earth's center = R₁

R₁ = H + R

R₁ = 3.2R + R

R₁ = 4.2R

Acceleration of the meteoroid due the Earth's gravitation = g₁

GM 91 = R

GM 91 = (4.2R)

GM 91 = 17,64R-

91 = 17,64

9.81 9117.64

g₁ = 0.556 m/s²

Acceleration of the meteoroid due to the Earth's gravitation = 0.556 m/s²