Question

-/3 POINTS ILLOWSKYINTROSTAT1 6.HW.068. The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.6 days and a standard deviation of 2.3 days. What is the probability of spending more than 3 days in recovery? (Round your answer to four decimal places.) Submit Answer ILLOWSKYINTROSTAT1 6.HW.069. The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.5 days and a standard deviation of 1.7 days. What is the 85th percentile for recovery times? (Round your answer to two decimal places.) ays

Answer 1

6 y Answers in Il consider X: the patient recovery time from a particular _scergical pəncedcere qixen theet, XNA Mlelis). ll= meana 5-6 days on Standard deviation : 2-3 days il we went to complete pl x>3) plx>8.) c.pl Xry > 3-4). - "ZE X-Ly AMCO) P(x>3) apla7 3-5.6 I 2 .3 = P(Z > -1.13) Z>N(0,1) C - 1-PC2<-113) 1 -P(Z > 1113) - 1-0.1292 = 0.8708 foom z table S 0.8708 -1.13 *. Answer: 0.8708

consider Xi Tbe patient recovery time from a peer tice- . -ler surgical procedure given that Xno Nil, o) = mean= 5.5 days os standard deviations 1.7 days suppose 85th percentile is ko is p(xsk) = 0.85 > P( 3 4 K-1 = 0.85 zzz xuyNC241) => pl z € K - 5.5 ) = 0.85 -0). v Plzs 1.04 ) =.0.85 from 2 table from (1) & @) K-5.5 = 1.04 => K-55 = 1:04 X1.7 . => K= 7.27 si 88 th percentile is 7.27 days Answer: __7. 27days -