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-/1.81 points IllowskylntroStat1 6.HW.068. The patient recovery time from a particular surgical procedure is normally distrib
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Answer #1

Solution :

Given that ,

mean = \mu = 5.6

standard deviation = \sigma = 1.9

P(x > 4) = 1 - P(x < 4)

= 1 - P((x - \mu ) / \sigma < (4 - 5.6) / 1.9)

= 1 - P(z < -0.84)

= 1 - 0.2005 Using standard normal table.

= 0.7995

Probability = 0.7995

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