concentration of NaOH = 0.050 M
volume = 20.2 mL
moles of NaOH = 0.050 x 20.2 / 1000
= 1.01 x 10^-3
moles of NaoH = moles of an acid
moles of acid = 1.01 x 10^-3
moles = mass / moalr mass
1.01 x 10^-3 = 60 x 10^-3 / Molar mass
Molar mass of an acid = 59.4 g/mol
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