Question

17. Given the following standard reduction potentials, E = +0.789 V Hg22 (aq) 2 Hg(%) + 2 e E = +0.271 V 2 Hg(A) 2 Cl (aq) 2

Please help with the following standard reduction potentials to determine the Ksp for Hg2Cl2(s) at 25 degree celsius.

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Answer #1

A: 0.5 1SV 2 2 E0 0591 ( 으:0591 -o . 5 is o59 ksp。anh log (e.sex2) 0 0591)

answered by: ANURANJAN SARSAM
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